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Find f'(x) f(x)÷1/(x-2)​

User Zhorian
by
5.0k points

1 Answer

1 vote

Answer:

f'(x) =
-(1)/((x-2)^2)

Explanation:

f(x) = 1/(x-2) = (x-2)^(-1)

power rule + chain rule:

f'(x) = -(x-2)^(-2) * 1

f'(x) =
-(1)/((x-2)^2)

User CAdaker
by
4.8k points