Answer:
1. If p is true and q is false, the p -> q is never true.
2. When p is false and q is true, then p or q is always true.
3. If p is true and ~ q is false, then p -> ~ q
N
is never false.
4. If p is true and q is true, then ~ p -> ~ q is always true.
5. If p->q is true and q is true, then p is
always true.
Further Explanation:
The logic gates are used here.
Here, the symbol -> is for implication. Implication p-> q means that if p is true then q must be true.
So let us look at all the questions one by one.
1. p is true and q is false, the p -> q is always, sometimes, never true.
p-> q
true -> false
The true should imply true so the given statement will never be true.
2. When p is false and q is true, then p or q is always, sometimes, never true.
false or true
We know that in or gate even if one input is true, the whole output is true. So this statement will be always true given p is false and q is true.
3. If p is true and~q is false, then P q is always, sometimes, never false.
This translates to:
true -> true
So it will never be false.
4. If p is true and q is true, then ^p -> ~q is always, sometimes, never true.
This translates to:
false false
This will always be true.
5. If p->q is true and q is true, then p is always, sometimes, never true.
If p->q is true and q is true then will always be true. "Implies to" states that in p->q, in order for q to be true p has to be true. So p will always be true.