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Write an equation of the line that passes through a pair of points:

(-2,-2), (5,-5)
A. Y=3/7x - 20/7
B. Y=-3/7x + 20/7
C. Y= -3/7x + 7/20
D. Y= -3/7x - 7/20

User Dimirsen Z
by
4.1k points

2 Answers

2 votes

Answer:

y = -(3/7)x - 20/7

Explanation:

Slope: (-5 - -2)/(5 - -2)

= -3/7

y = (-3/7)x + c

-2 = (-3/7)(-2) + c

-2 - 6/7 = c

c = -20/7

y = -(3/7)x - 20/7

User Zoeb S
by
2.9k points
3 votes

Answer:

Explanation:

(-2,-2) , (5,-5)


Slope=(y_(2)-y_(1))/(x_(2)-x_(1))\\\\=(-5-(-2))/(5-(-2))\\\\=(-5+2)/(5+2)\\\\=(-3)/(7)\\

(-2,-2), m= -3/7

Line equation: y -y1 =m*(x -x1)

y-(-2) = -(-3/7)(x - [-2])


y+2=(-3)/(7)*(x+2)\\\\y+2=(-3)/(7)*x+((-3)/(7))*2\\\\y+2=(-3)/(7)x-(6)/(7)\\\\y=(-3)/(7)x-(6)/(7)-2\\\\y=(-3)/(7)x-(6)/(7)-(2*7)/(1*7)\\\\y=(-3)/(7)x-(6)/(7)-(14)/(7)\\\\y=(-3)/(7)x-(20)/(7)

User MarkusAtCvlabDotDe
by
3.3k points