Question

2x+3y=12 find four solutions​

Answer 1

1. x=3,y=2

2.x=0,y=4

3.x=-3,y=6

4.x=6,y=0

Explanation:

x=3, y=2

2(3)+3(2)=6+6=12

x=0, y=4

2(0)+3(4)=0+12=12

x=-3, y=6

2(-3)+3(6)=-6+18=12

x=6,y=0

2(6)+3(0)=12+0=12. Hope this helps!