Question

What are the solutions to the equation and check for extraneous solutions:

16=(x-2)^2/3

Answer 1

we have x = -62 or x = 66

Explanation:

16=(x-2)^2/3

I would take square root first

4 = (x - 2)^ (1/3)

or -4 = (x - 2)^(1/3)

.....

4^3 = x - 2

64 = x - 2

x = 66

or -4 ^3 = x - 2

-64 = x - 2

x = -62

we have x = -62 or x = 66