Answer:
I = 2330.9 A
Step-by-step explanation:
The magnitude of the current produced by the metal of 1 kg has been 2330.9 A.
In electrophoresis, the transfer of 2 moles of electrons takes place per mole of Na.
The moles of sodium has been:
Moles =
Moles of Na = mol
Moles of Na = 43.47 mol
1 mole Na have = 2 moles electrons transfer
The total charge transfer in 1000 grams Na can be given by:
q = moles of Na moles of electrons transfer Faraday constant
q = 43.47 2 96500
q = 8.391 C
The current can be given by:
I =
I =
I = 2330.9 A
The magnitude of the current produced by the metal of 1 kg has been 2330.9 A.