Question

What is the mass (g) of 7.32x10^15 atoms of (Sn)

Answer 1

The mass of Sn in 7.32 *10^15 atoms is 1.43*10^-6 grams

Step-by-step explanation:

1 mole = 6.02 *10^23 atoms (Avogadro's constant)

6.02 *10^23 atoms = 1 mole

7.32*10^15 atoms = (7.32*10^15 / 6.02 *10^23) moles of Sn

= 1.22 *10^-8 atoms of Sn.

The relationship between umber of moles and mass is thus;

n = m / mm; where m = mass, mm = molar or atomic weight, n = number of moles

m = n * mm

mm of Sn = 118g/mol

m = 1.22 *10^-8 * 118

m = 0.000001403 g

m = 1.43 *10^-6 g

The mass of Sn in 7.32 *10^15 atoms is 1.43*10^-6 grams

Answer 2

144.7×10^-8g of tin

Step-by-step explanation:

Recall from Avogadro's law that the number of elementary entities (atoms, molecules, ions etc) in one mole of a substance is equal to the Avogadro's number which has a numerical equivalent of 6.02×10^23.

1 mole of tin has a mass of 119g

Hence 119g of tin has 6.02 ×10^23 atoms of tin

x g of tin will have 7.32x10^15 atoms of tin

x= 7.32x10^15 × 119/ 6.02 ×10^23

x= 144.7×10^-8g of tin