Answer:
Answer: y=2x+13.
Explanation:
Your input: find the equation of the line perpendicular to the line y=5/2−x/2 passing through the point (−4,5).
The equation of the line in the slope-intercept form is y=5/2−x/2.
The slope of the perpendicular line is negative inverse: m=2.
So, the equation of the perpendicular line is y=2x+a.
To find a, we use the fact that the line should pass through the given point: 5=(2)⋅(−4)+a.
Thus, a=13.
Therefore, the equation of the line is y=2x+13.
Answer: y=2x+13.