Question

Ajoba and Prav drive to work. Ajoba drives 45 miles in 2.5 hours. Prav drives 74 km in 1 hour 15 minutes. Work out the difference between their average speed in km/h. 1 mile = 1.6 km

Answer 1

Ajoba: 28.8km/h

Prav: 59.2km/h

The difference in speed is: 59.2-28.8=30.4km/h

Explanation:

Ajoba:

d=45mi Convert to km //
`45mi((1.6km)/(1mi) )=72km`

t=2.5h

v=? 28.8km/h

Prav:

d=74km

t=1h15m or 1.25h

v=? 59.2km/h

`Formula: d=v*t`

Solve for v;

`v=(d)/(t)`

`v=(72km)/(2.5h) \\v=28.8km/h`

--------------------------------------------

`v=(d)/(t)`

`v=(74km)/(1.25h) \\v=59.2km/h`