Question

The sum of the digits of a three digit number is 19. The second digit is one more than the first digit. The third

digit is two more than the second digit. Find the number.
A. 890
B. 124
C. 345
D. 568

Answer 1

• D. 568

Explanation:

Let the number is in the form of xyz

We have

Sum of the digits is 19

• x + y + z = 19

The second digit is one more than the first digit

• y = x + 1

The third digit is two more than the second digit

• z = y + 2 = x + 1 + 2 = x + 3

Substitute the values of y and z into the first equation and solve for x

• x + x + 1 + x + 3 = 19
• 3x + 4 = 19
• 3x = 15
• x = 5

Find the value of y and z

• y = 5 + 1 = 6
• z = 5 + 3 = 8

The number is 568