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In ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. Find the measure of ∠J to the nearest degree.

User Nanobar
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2 Answers

6 votes

Answer:

24∘

Explanation:

User Pmjobin
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1 vote

We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.

First of all, we will draw a triangle as shown in the attachment.

We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.

We know that sine relates opposite side of right triangle to hypotenuse.


\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}


\text{sin}(\angle J)=(22)/(54)

Using inverse sine or arcsin, we will get:


\angle J=\text{sin}^(-1)((22)/(54))


\angle J=24.042075905756^(\circ)

Upon rounding to nearest degree, we will get:


\angle J\approx 24^(\circ)

Therefore, the measure of angle J is approximately 24 degrees.

In ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. Find the measure of-example-1
User Bboe
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