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Zn + 2HCl = ZnCl3 + H2: How many grams of ZnCl3 will be produced from 22 g of Zn and 14 g of HCl?

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So, first, convert 22g of Zn to moles, and 14g of HCl to moles, and use a b delta a table to find moles of ZnCl3 are produced (0.192 mol)
Zn + 2HCl = ZnCl3 + H2: How many grams of ZnCl3 will be produced from 22 g of Zn and-example-1
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