Question

Q.
(5sin 87° + tan 72° - sec 5°) / (cot 18° - cosec 85°+ 5cos 3°)​

Answer 1

`(5 \sin 87^(\circ) + \tan 72^(\circ) - \sec 5^(\circ))/(\cot 18^(\circ)-\csc 85^(\circ)+5\cos 3^(\circ))\\\\\\=(5\sin\left(90^(\circ)-3^(\circ) \right) + \tan\left(90^(\circ)-18^(\circ) \right)-\sec\left(90^(\circ)-85^(\circ) \right))/(\cot 18^(\circ)-\csc 85^(\circ)+5\cos 3^(\circ))\\\\\\=(5\cos 3^(\circ) + \cot 18^(\circ)-\csc 85^(\circ))/(\cot 18^(\circ)-\csc 85^(\circ)+5\cos 3^(\circ))\\\\\\=1`