Question

What is the mass, in grams, of 0.00948\,\text {mol}0.00948mol0, point, 00948, start text, m, o, l, end text of phosphoric acid?

Answer 1

`m = 0.929\,g`

Step-by-step explanation:

The formula for the phosphoric acid is
`H_(3)PO_(4)`, whose molecular weight is
`97.994\,(g)/(mol)`. The mass in grams of the sample is computed afterwards:

`m = (0.00948\,mole)\cdot (97.994\,(g)/(mol) )`

`m = 0.929\,g`

Answer 2

0.929g

Step-by-step explanation:

The following were obtained from the question.

Number of mole of phosphoric acid (H3PO4) = 0.00948mol.

Mass of H3PO4 =?

The mass in grams of phosphoric acid (H3PO4) can be obtained as follow:

Number of mole of H3PO4 = 0.00948mol.

Molar Mass of H3PO4 = (3x1) + 31 + (16x4) = 3 + 31 + 64 = 98g/mol

Mass of H3PO4 =?

Mass = number of mole x molar Mass

Mass of H3PO4 = 0.00948 x 98

Mass of H3PO4 = 0.929g