Answer:
0.0015 or 0.15%
Explanation:
Data
- mean age of sea turtles, μ: 80 years
- standard deviation, σ: 17.3 years
Z score is defined as:
Z = (x - μ)/σ
To find the probability of finding a sea turtle that is over the age of 131.9 years, we have to replace x = 131.9, to get:
Z = (131.9 - 80)/17.3 = 3
The 68 - 95 - 99.7 rules stands that (see figure attached):
P(Z > 3) = 0.0015