Question

What is the x-intercept of the function y = log2 (x - 5)?

Answer 1

(6, 0 )

Explanation:

To find the x- intercept let y= 0 and solve for x

Using the rule of logarithms

`log_(b)` x = n ⇒ x =
`b^(n)`, thus

`log_(2)` (x - 5) = 0

x - 5 =
`2^(0)` = 1 ( add 5 to both sides )

x = 6

x- intercept = (6, 0 )

Answer 2

Explanation:

`y=log_(2)(x-5)\\or~ x-5=2^y\\when y=0\\x-5=2^0=1\\x=1+5=6\\x~intercept~is~(6,0)`