Using similar triangle
We notice that,
Both triangles have the same angle base
Then, <A ≈ <A
Also, from corresponding angle
<F ≈ <B
And < C ≈ <G
Using this, since the three angles of the triangles are equal, then we can write their similarities from their angle
∆F AG ≈ ∆BAC
Let assume one square of the graph represent one unit
So, ∆F AG ≈ ∆BAC
|F A| / ||BA| = |FG| / |BC| = |AG| / |AC|
|F A| = 9 Square units
|BA| = 3 Square units
|AC| = 2 Square units
|AG| = 6 Square units
|F A| / |BA| = |AG| / |AC|
|F A| / ||BA| = 9 / 3 = 3
|AG| / |AC| = 6 / 2 = 3
Then,
|F A| / |BA| = |AG| / |AC| = 3
Then,
The second option is correct
<A ≈ <A, |A F| / |AB| = |AG| / |AC| = 3