Question

Not sure how to do this

Answer 1

0.0991 M

Step-by-step explanation:

Step 1: Write the neutralization reaction between oxalic acid and sodium hydroxide.

H₂C₂O₄ + 2 NaOH = Na₂C₂O₄ + 2 H₂O

Step 2: Calculate the moles of oxalic acid

The molar mass of H₂C₂O₄ is 90.03 g/mol. The moles corresponding to 153 mg (0.153 g) are:

`0.153g * (1mol)/(90.03g) = 1.70 * 10^(-3) mol`

Step 3: Calculate the moles of sodium hydroxide

The molar ratio of H₂C₂O₄ to NaOH is 1:2.

`1.70 * 10^(-3) molH_2C_2O_4 * (2molNaOH)/(1molH_2C_2O_4) = 3.40 * 10^(-3) molNaOH`

Step 4: Calculate the molarity of sodium hydroxide

`(3.40 * 10^(-3) mol)/(34.3 * 10^(-3) L) = 0.0991 M`