Answer:
2x+y=0
Explanation:
Given:
![\displaystyle \large{2x+y=4}\\\displaystyle \large{y=-2x+4}](https://img.qammunity.org/2023/formulas/mathematics/middle-school/aq3pe26w926nu7kd6wr7y9x9ajq3xrhlax.png)
To find:
- The equation of line that’s parallel and passes through origin point.
Parallel Definition:
- Both lines have same slope.
Slope-Intercept:
![\displaystyle \large{y=mx+b}](https://img.qammunity.org/2023/formulas/mathematics/middle-school/xeh4f4rld4lh1dugmirqcb0oo9957krg2p.png)
Therefore, another line is:
![\displaystyle \large{y=-2x+b}](https://img.qammunity.org/2023/formulas/mathematics/middle-school/yba5m024ikyvnjs7ffx8i7w91dht9d547h.png)
Since the line passes through origin point which is (0,0). Substitute x = 0 and y = 0 in the equation:
![\displaystyle \large{0=-2(0)+b}\\\displaystyle \large{b=0}](https://img.qammunity.org/2023/formulas/mathematics/middle-school/6h76s5w7br7a1ho6f655q6n5grrjhanwom.png)
Therefore, the equation is:
![\displaystyle \large{y=-2x}](https://img.qammunity.org/2023/formulas/mathematics/middle-school/ts8gtapjktl4iatfdzhwh6re3oubbko566.png)
Convert back to standards form:
![\displaystyle \large{2x+y=0}](https://img.qammunity.org/2023/formulas/mathematics/middle-school/r39zf6i28w0xbbjoe5lcu6eiefg57ioi1r.png)
Therefore, another line that is parallel to
is 2x+y=0