Explanation:
Juan wants to know the cross-sectional area of a circular pipe. He measures the diameter which he finds, to the nearest millimetre, to be 5 centimetres
It means radius is 2.5 cm. For the area of circle he gets the formula as :
![A=\pi r^2\\\\A=3.14* (2.5)^2\\\\A=19.62\ cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/gdskx2209xoei7eij4kghwcs4ms30yhdxm.png)
If Michelle found the area of a circle as
![A=78.5\ in^2](https://img.qammunity.org/2021/formulas/mathematics/college/jajwpdx8wz7gsogcwkp9lmsakutca3wwme.png)
So,
![A=\pi r^2\\\\r=\sqrt{(A)/(\pi)} \\\\r=\sqrt{(78.5)/(3.14)} \\\\r=5\ \text{inch}](https://img.qammunity.org/2021/formulas/mathematics/high-school/w5ixx78v9gbdnm98tdl21520nvfx308g7b.png)