Question

A student places a 50.0 g sample of a metal at 96.8° C into a calorimeter full of 100.0 g of

water (specific heat of water = 4.18 J/g°C). The water, initially at 22.0 °C, eventually
comes to a temperature of 25.9 °C. Calculate the heat gained by the water.

Answer 1

1630.2 j

Step-by-step explanation:

100 gm * 4.18 J/gm-C * ( 25.9-22 C ) = 1630.2 j