Question

A balloon contains 2500. mL of Helium at 75.00°C. When the temperature is lowered to

-25.00 °C and the pressure remains unchanged, what is the new volume?

Answer 1

+75°C = 273+75 = 348 K

-25 °C = 273 - 25=248 K

now as at constant pressure, V/T = constant

so

2500/348 = V/248

Step-by-step explanation:

V = 2500/348 × 248 = 1781.6 mL