Question

Solve logx = -3 by changing it to exponential form.

A.x=1/10^3
B.x=-30
C.x=30
D.x=1/3^10

Answer 1

A

Explanation:

Using the rule of logarithms

`log_(b)` x = n ⇒ x =
`b^(n)`

Given

`log_(10)` x = - 3, then

x =
`10^(-3)` =
`(1)/(10^(3) )` → A