Question

Please help me with this as soon as possible. It's due today!

Answer 1

#5= 52^0 (52 degree)-- A

#6=107^0 --S

#7=100^0--H

#8=80^0--I

#9=100^0--H

#10=115^0--E

#11=65^0--U

#12=115^0--E

#13=36^0--T

#14=144^0--W

#15=36^0--T

#16=52^0--A

#17=23^0--D

#18=90^0--O

#19=36^0--T

#20=60^0--R

#21=30^0--Q

#22=60^0--R

Explanation:

#5. A circle has 360 degree. half circle 180 degree; therefore 180^0-128^0= 52^0.

graph 3. #7,#8,#9, it has an angle 80 degree, so we can find #7=180^0-80^0=100^0, and #9=180^-80^0=100^0; therefore, #8=80^0, a circle is always 360 degree.

other has the same logic

Answer 2

1-4 are not there but here it is without them