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Write the equation of the line that passes through the points (5, - 1) an (7,-7)

User Makenshi
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2 Answers

3 votes

Final answer:

To find the equation of the line passing through (5, -1) and (7, -7), calculate the slope which is -3, then use the point-slope form with one of the points to get y = -3x + 14.

Step-by-step explanation:

Finding the Equation of a Line

To write the equation of a line that passes through the points (5, -1) and (7, -7), we need to first calculate the slope of the line. The slope can be determined from the following formula:

Slope (m)

= Δy / Δx = (y2 - y1) / (x2 - x1)

By substituting the given points into the formula, we get:

Slope (m) = (-7 - (-1)) / (7 - 5) = -6 / 2 = -3

Now that we have the slope, we can use one of the points and the slope to write the equation in point-slope form:

y - y1 = m(x - x1)

Using the point (5, -1), the equation becomes:

y + 1 = -3(x - 5)

Finally, we can convert this to slope-intercept form by simplifying:

y + 1 = -3x + 15

y = -3x + 14

Therefore, the final equation of the line in slope-intercept form is y = -3x + 14.

User Gerrard
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5.8k points
2 votes
m=y2-y1/x2-x1
m=-7+1/7-5
m=-6/2 but Simplified Its -3/1 or -3
User Meire
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5.3k points