given:
first trip= 50 miles.
second trip= 300 miles.
to find:
his new time compared to the old time.
solution:
Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.
Speed = Distance/Time
So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.
= 100/x hr
Therefore, his new time compared with the old time was twice as much.
answer= b) twice as much