Answer:
1,736.1N
Step-by-step explanation:
The information we have is:
mass:
![m==1,250kg](https://img.qammunity.org/2021/formulas/physics/middle-school/zcdfkiv8xk6hdmwyd0wpy5zqo3nk91esv5.png)
initial velocity:
![v_(i)=0](https://img.qammunity.org/2021/formulas/physics/middle-school/ev2vu3i4epicc0hsed1kaachnfalvhsjns.png)
final velocity:
![v_(f)=50km/h](https://img.qammunity.org/2021/formulas/physics/middle-school/tzrvityvtfbugjdtzame0qfs8liw30b82f.png)
we need to converto to m/s:
![v_(f)=(50km)/(h)*(1h)/(3,600s) *(1000m)/(1km) \\v_(f)=13.89m/s](https://img.qammunity.org/2021/formulas/physics/middle-school/6mmeucybudpy3mgl1dyzv9vulyr38o9m2h.png)
time:
.
First we need to calculate the acceleration:
![a=(v_(f)-v_(i))/(t)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wuifqxep9rn2na3di7oav13ins9nw2gry0.png)
substituting the values:
![a=(13.89m/s-0)/(10s) \\a=1.389m/s^2](https://img.qammunity.org/2021/formulas/physics/middle-school/jxvcr3b79a4v0elhs1xmo12lk5v7bznnm6.png)
and now we use Newton's second law to calculate the net force:
![F=ma](https://img.qammunity.org/2021/formulas/physics/college/kxqi3lxi3fjfv761qhdu0s1p00agxd9vve.png)
substituting the mass and acceleration:
![F=(1250kg)(1.389m/s ^2)\\\\F=1,736.1N](https://img.qammunity.org/2021/formulas/physics/middle-school/tgnmoaxps5m0yn3biwa1yltbn4ar1yz2xo.png)
the net force on the vehicle is in Newtons is: 1,736.1N