Question

In a certain normal distribution of scores, the mean is 50 and the standard deviation is 6. Find the Z-score corresponding to a score

of 60.
a. -1.67
c. 1.67
b. 10.0
d. 8.33

Answer 1

Option c.

Explanation:

Given information:

Mean = 50

Standard deviation = 6

Observed value = 60

We need to find the Z-score.

Formula for Z score is,

`Z=(x-\mu)/(\sigma)`

where, x is observed values,
`\mu` is mean and
`\sigma` is standard deviation.

Substitute the given values in the above formula.

`Z=(60-50)/(6)`

`Z=(10)/(6)`

`Z=1.6666...`

`Z\approx 1.67`

Therefore, the correct option is c.