The measures of the angles are:
![\[ \angle KJL = 100^\circ, \quad \angle NJM = 155^\circ, \quad \angle MJL = 105^\circ \]](https://img.qammunity.org/2021/formulas/mathematics/high-school/3k0n3iui1tn2h5dj12ui5rxlkvxvjj6lh4.png)
Given that KJN is a straight line, we know that the sum of the angles along this line is
. Therefore, we can express this relationship as:
![\[ \angle LJK + \angle LJM + \angle MJN = 180^\circ \]](https://img.qammunity.org/2021/formulas/mathematics/high-school/sf6n0wjhnwt5cs4akx55o5xlrwji55n5um.png)
Now, substitute the given values:
(3x + 5) + 75 + x = 180
Combine like terms:
4x + 80 = 180
Subtract 80 from both sides:
4x = 100
Divide by 4:
x = 25
Now that we have the value of x, we can find each angle:
1. Angle KJL (by angle sum property in triangle KJL):
![\[ \angle KJL = 180^\circ - \angle LJK = 180^\circ - (3x + 5) = 180^\circ - (3 * 25 + 5) = 180^\circ - 80 = 100^\circ \]](https://img.qammunity.org/2021/formulas/mathematics/high-school/h7sdd5qnv50v6ksbaeu5b2koqoss7s95xn.png)
2. Angle NJM (by angle sum property in triangle NJM):
![\[ \angle NJM = 180^\circ - \angle MJN = 180^\circ - x = 180^\circ - 25 = 155^\circ \]](https://img.qammunity.org/2021/formulas/mathematics/high-school/tlc5e46kgdnyl5p2hmm5dbu7nedat2a879.png)
3. Angle MJL (by angle sum property in triangle MJL):
![\[ \angle MJL = 180^\circ - \angle LJM = 180^\circ - 75 = 105^\circ \]](https://img.qammunity.org/2021/formulas/mathematics/high-school/d1qvf1frdbczyjsaa7lt4wc2d1z2actc1k.png)
Therefore, the measures of the angles are:
![\[ \angle KJL = 100^\circ, \quad \angle NJM = 155^\circ, \quad \angle MJL = 105^\circ \]](https://img.qammunity.org/2021/formulas/mathematics/high-school/3k0n3iui1tn2h5dj12ui5rxlkvxvjj6lh4.png)