Answer:
4) -23
Explanation:
sub 2 for x in j(x) and evalueate
then sub that result for x in h(x)
j(2)=-2(2)
j(2)=-4
now sub-4 for x in h(x)
h(-4)=5(-4)-3
h(-4)=-20-3
h(-4)=-23
answer is -23
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