Question

Find the sum of the series.

Series from 0 to infinity

`(7^n)/(n!3^n)`

Answer 1

Recall that

`e^x=\displaystyle\sum_(n=0)^\infty(x^n)/(n!)`

Plug in
`x=\frac73` and you get your series, so the given series has a value of
`e^(7/3)`.