Answer:
B.) 1.13s; 27.25ft
Explanation:
Ok so this is an projectile motion equation...
Haven't done one of these in a while but I could definitely try!
To do this, we need to use this particular equation

We can substitute values into the equation to get the time it takes to reach the maximum height!

This is the same as...

We now know that it takes 1.13 seconds for the ball to reach its maximum height!
We can insert that into the original equation and simplify to get this answer:

Alright so it's not exactly 27.25 but you get the gist.