Question

What is the solution to the equation below?

Blog4x = log232+ log 2
O X=-8
O
X=-4
O x=4
X-
X-8

Answer 1

x = 4

Explanation:

When you have a coefficent in front of a logarithm function, you can take the argument to the power of that coefficient. For example, the 3 in front of the logarithm can be brought into the argument, and you can take 'x' to the third power. You get:

`log_(4)( {x}^(3) ) = log_(4)(32) + log_(4)(2)`

When you add logarithms, it is equivalent to multiplying their arguments:

`log_(4)( {x}^(3) ) = log_(4)(32 * 2) = log_(4)(64)`

Since both sides are log base 4, the arguments must equal each other:

`{x}^(3) = 64`

`x = \sqrt[3]{64} = 4`

Answer 2

here it is, this is ur answer x=4