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Angles and Parallel Lines

Angles and Parallel Lines-example-1
User Bilpor
by
8.5k points

1 Answer

6 votes

Answer:

a = 6

b = 25

Explanation:

As alternative angles in a parallel line are equal to each other,

5a = 3a + 12

So, now we can find the value of a by making "a" the subject.

5a - 3a = 12

2a = 12

Divide both sides by 2.

a = 6°

And now let us find the value of b.

We know that interior angles in a triangle are added up to 180°.

So,

2b + 4b + 3a + 12 = 180

We can replace a with 6 and then we can make "b" the subject to find the value of b.

Let us solve it now.

2b + 4b + 3 × 6 + 12 = 180

6b + 18 + 12 = 180

6b + 30 = 180

6b = 180 - 30

6b = 150

Divide both sides by 6.

b = 25°

User Lockdoc
by
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