Answer:
The number of subscribers in 2008 is 110,845,988
Explanation:
The number of cell phone subscribers in Arlington, in t years after 1985, can be modeled by the following equation.
![N(t) = N(0)(1+r)^(t)](https://img.qammunity.org/2021/formulas/mathematics/college/coodswgqfdfsih2xsggv3y46ryqlox785c.png)
And which N(0) is the number of subscribers in 1985 and r is the rate it increases per year, as a decimal.
In 1985, there were 285 cell phone subscribers in Arlington.
This means that
![N(0) = 285](https://img.qammunity.org/2021/formulas/mathematics/college/2u8jk7txkb62ndpdizlty37kqpdti29yt9.png)
The number of subscribers increased by 75% per year since 1985.
This means that
![r = 0.75](https://img.qammunity.org/2021/formulas/mathematics/college/1x427wof77rtnml1lo4erc69ogyk1pbdp6.png)
So
![N(t) = 285(1.75)^(t)](https://img.qammunity.org/2021/formulas/mathematics/college/qtkji209fkgzu9wiwisu9agwxo7dujwlxb.png)
Find the number of subscribers in 2008.
2008 is 2008-1985 = 23 years after 1985. So we have to find N(23).
![N(23) = 285(1.75)^(23) = 110,845,988](https://img.qammunity.org/2021/formulas/mathematics/college/38axwewkcq9ejm91mqmvayzx2ckenymgvd.png)
The number of subscribers in 2008 is 110,845,988