Question

- How many moles of HCl will be needed to neutralize 200.0 ml of a 2.5 M NaOH solution?

Answer 1

0.5 mol HCl

Step-by-step explanation:

2.5 mol/L *0.200 L = 0.5 mol NaOH

NaOH + HCl ---> NaCl + H2O

from reaction 1 mol 1 mol

given 0.5mol x mol

x= 0.5*1/1= 0.5 mol HCl