Question

A sheet of copper is 5 mm thick and has

surface dimensions of 7 cm × 22 cm .
If the long edges are joined to form a
tube 22 cm in length, what is the resistance between the ends? The mass density
of copper is 8920 kg/m3
and its resistivity is
1.7 × 10−8 Ω · m .
Answer in units of Ω

Answer 1

`R=2.42* 10^(-7)\ \Omega`

Step-by-step explanation:

We have,

Dimension of the sheet is 7 cm × 22 cm.

Length of the tube, l = 22 cm

Resistivity of the copper wire is
`\rho=1.7* 10^(-8)\ \Omega-m`

It is required to find the resistance between the ends. We know that the formula of resistance is given by :

`R=\rho (l)/(A)`

A is area of sheet

`R=1.7* 10^(-8)* (0.22)/(0.07* 0.22)\\\\R=2.42* 10^(-7)\ \Omega`

So, the resistance between the ends is
`2.42* 10^(-7)\ \Omega`.