Question

A transformer has input voltage and current of 12 V and 4 A

respectively, and an output
current of 0.8 A. If there are 1177 turns turns on the
secondary side of the transformer, how many
turns are on the primary side? 4 significant digits please.

Answer 1

Step-by-step explanation:

It is given that,

Input voltage,
`V_i=12\ V`

Input current,
`I_i=4\ A`

Output current,
`I_o=0.8\ A`

Number of turns in the secondary side of transformer,
`N_s=1177`

We need to find the number of turns in the primary side of the transformer. The current to the number of turns in the input and output is given by :

`(N_s)/(N_p)=(I_p)/(I_s)`

Substituting all the above values

So,

`N_p=(N_sI_s)/(I_p)\\\\N_p=(1177* 4)/(0.8)\\\\N_p=5885`

So, the number of turns in primary side of the transformer is 5885.