Question

What is the volume of 0.120 g of C2H2F4

vapor at 0.970 atm and 22.4°C?
Answer in units of L.

Answer 1

V= 0.031L

Step-by-step explanation:

P= 0.97atm, V= ?, n= 0.12/98 =0.00122mol, R= 0.082, T= 22.4+273= 295.4

Applying

PV=nRT

0.970×V = 0.00122×0.082×295.4

Simplify the above equation

V= 0.031L