Question

What volume of 6.58M HCI is needed to make 500. mL of 3.00M HCI?

Answer 1

228 mL

Step-by-step explanation:

M1*V1 = M2*V2

M1 = 6.58 M

V1 = ?

M2 = 3.00 M

V2 = 500 mL

V1 = M2*V2/M1 = 3.00M*500.mL/6.58 M = 228 mL