Question

In a hydraulic lift, if you exert a downward force of 100 N on a piston with an area of 1 m^3, how much upward force would be exerted on a piston with an area of 20 m^3?

Answer 1

`F_2=2000\ N`

Step-by-step explanation:

We have,

Area 1,
`A_1=1\ m^3`

Force 1,
`F_1=100\ N`

Area 2,
`A_2=20\ m^3`

It is required to find the force 2. In a hydraulic lift, the pressure at two points is same. It means :

`P_1=P_2\\\\(F_1)/(A_1)=(F_2)/(A_2)`

`F_2=(F_1A_2)/(A_1)\\\\F_2=(100* 20)/(1)\\\\F_2=2000\ N`

So, second force is 2000 N.