Question

To how much water should 250 mL of 12 M hydrochloric acid be added to

produce a 4.0 M solution?

Answer 1

500ml water

Step-by-step explanation:

Molarity x Volume in liters (concentrated soln) = Molarity x Volume (diluted soln) ∴

250ml X 12M HCl = 4M x Volume of diluted solution

=> Volume of diluted solution = (250ml)(12M)/(4m) = 750 ml final solution vol. after mixing.

So the amount of water added to the 250ml of 12M acid = 750ml - 250ml = 500ml of water.