Answer:
For N₂F₂:
Molar fraction = 0.84
Partial pressure = 1.12 atm
For SF₄:
Molar fraction = 0.16
Partial pressure = 0.208 atm
Step-by-step explanation:
It seems your question is missing the values required to solve the problem. However, an internet search showed me the following values for your question. If the values in your problem are different, your answer will be different as well, however the solving method will remain the same:
" A 5.00L tank at 0.7°C is filled with 16.5g of dinitrogen difluoride gas and 5.00g of sulfur tetrafluoride gas. You can assume both gases behave as ideal gases under these conditions. "
First we calculate the moles of each gas, using their molar mass:
- 16.5 g N₂F₂ ÷ 66 g/mol = 0.25 mol N₂F₂
- 5.00 g SF₄ ÷ 108 g/mol = 0.0463 mol SF₄
Total mol number = 0.25 + 0.0463 = 0.2963 mol
- Mole Fraction N₂F₂ = 0.25/0.2963 = 0.84
- Mole Fraction SF₄ = 0.0463/0.2963 = 0.16
Now we use PV=nRT to calculate the partial pressure of each gas:
P = ?
V = 5.00 L
T = 0.7 °C ⇒ 0.7 + 273.16 = 273.86 K
For N₂F₂:
- P * 5.00 L = 0.25 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 273.86 K
For SF₄:
- P * 5.00 L = 0.0463 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 273.86 K