Question

If 0.545J of heat leads to a 0.892 degree C change, what mass of water is present?

Answer 1

I got .146 g of water

Step-by-step explanation:

Refer to this equation:

Q= mcΔt

Q= .545 J

c= 4.186 J/g

Δt= .892

plug in values:

.545 J = m(4.186 J/g)(.892°C)

simplify:

.545 J = m(3.734 J/g°C)

.146 g