Question

Question 5 (1 point)

A gas in a 100 L tank at 25 degrees Celsius exerts a pressure of 19 atm. The gas is cooled to 0 degrees Celsius and pumped into a 20 L tank.
What pressure will it exert under these new conditions?
OOOO
35 atm
46 atm
87 atm
104 atm​

Answer 1

Answer : The pressure it exert under these new conditions will be, 87 atm

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 19 atm

`P_2` = final pressure of gas = ?

`V_1` = initial volume of gas = 100 L

`V_2` = final volume of gas = 20 L

`T_1` = initial temperature of gas =
`25^oC=273+25=298K`

`T_2` = final temperature of gas =
`0^oC=273+0=273K`

Now put all the given values in the above equation, we get:

`(19atm* 100L)/(298K)=(P_2* 20L)/(273K)`

`P_2=87atm`

Therefore, the pressure it exert under these new conditions will be, 87 atm