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If I invested $4500 at 10% compounded monthly. How much would be in the account in 3 years? Round to nearest cent

1 Answer

4 votes

Answer:

$6,066.82

Explanation:

Lets use the compound interest formula provided to solve this:


A=P(1+(r)/(n) )^(nt)

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, change 10% into a decimal:

10% ->
(10)/(100) -> 0.10

Since the interest is compounded monthly, we will use 12 for n. Lets plug in the values now:


A=4,500(1+(0.10)/(12))^(12(3))


A=6,066.82

The balance after 3 years will be $6,066.82

User Pavi
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