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Does x^2-6x+3 have solutions that are real numbers

User Mahouk
by
6.2k points

1 Answer

2 votes

Answer:

X=10.8 and X=1.1

Explanation:

Δ= b^2-4ac

= (-6)^2-4(1)(3)

=24

X1=


\frac{6 + √(24) }{ {1}^(2) }

=10.8

X2=


\frac{6 - √(4) }{ {1}^(2) }

=1.1

User Yergo
by
5.9k points