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(1)=−10 h(2)=−2 h(n)=h(n−2)⋅h(n−1) h(3)=
asked
Oct 16, 2021
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(1)=−10
h(2)=−2
h(n)=h(n−2)⋅h(n−1)
h(3)=
Mathematics
high-school
DMurdZ
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DMurdZ
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2
Answers
2
votes
Answer:
6
Explanation:
Paul Stovell
answered
Oct 18, 2021
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Paul Stovell
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4
votes
Answer:
20
Explanation:
h(3)=h(1)*h(2)=
(-10)*(-2)=
20
Raffaela
answered
Oct 22, 2021
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Raffaela
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