Question

A gas occupies a volume of 1.00 L at 25.0°C. What volume will the gas occupy at 1.00 x10^2 °C?

Answer 1

Answer : The volume of gas occupy at
`1.00* 10^2^oC` is, 1.25 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

`(V_1)/(T_1)=(V_2)/(T_2)`

where,

`V_1\text{ and }T_1` are the initial volume and temperature of the gas.

`V_2\text{ and }T_2` are the final volume and temperature of the gas.

We are given:

`V_1=1.00L\\T_1=25.0^oC=(25.0+273)K=298K\\V_2=?\\T_2=1.00* 10^2^oC=((1.00* 10^2)+273)K=373K`

Putting values in above equation, we get:

`(1.00L)/(298K)=(V_2)/(373K)\\\\V_2=1.25L`

Therefore, the volume of gas occupy at
`1.00* 10^2^oC` is, 1.25 L