Answer:
The probability that a randomly selected person from this sample liked recreational reading or disliked recreational reading is 1.
Explanation:
The probability of an event E is the ratio of the favorable number of outcomes to the total number of outcomes.

Mutually exclusive events are those events which cannot occur together. They are also known as disjoint events.
If events A and B are mutually exclusive then:

The data provided is:
Opinion Like academic Dislike academic Total
reading reading
Liked recreational 136 40 176
reading
Disliked recreational 16 8 24
reading
Total 152 48 200
Denote the events as follows:
X = a person liked recreational reading.
Y = a person disliked recreational reading.
Compute the probability that a randomly selected person from this sample liked recreational reading or disliked recreational reading as follows:


Thus, the probability that a randomly selected person from this sample liked recreational reading or disliked recreational reading is 1.